40d+16d^2=-25

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Solution for 40d+16d^2=-25 equation: 



40d+16d^2=-25

We move all terms to the left:

40d+16d^2-(-25)=0

We add all the numbers together, and all the variables

16d^2+40d+25=0

a = 16; b = 40; c = +25;
Δ = b2-4ac
Δ = 402-4·16·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{-40}{32}=-1+1/4$

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